Sanford is a city located in Seminole County, Florida. Sanford has a 2026 population of 69,829. It is also the county seat of Seminole County. Sanford is currently growing at a rate of 2.13% annually and its population has increased by 14.29% since the most recent census, which recorded a population of 61,098 in 2020.
The median household income in Sanford is $66,891 with a poverty rate of 11.89%. The median age in Sanford is 37.1 years: 35.9 years for males, and 38.4 years for females. For every 100 females there are 96.8 males.
Data after 2023 is projected based on recent change
Overall: 37.1 years
Female: 38.4 years
Male: 35.9 years
There are 50,731 adults, (8,489 of whom are seniors) in Sanford.
Female: 32,379 (50.8%)
Male: 31,351 (49.2%)
The racial composition of Sanford includes 41.47% White, 24.54% Black or African American, 7.56% other race, 4.4% Asian, and smaller percentages for Native American, Native Hawaiian or Pacific Islander and multiracial populations.
| Race | Population ↓ | Percentage (of total) |
|---|---|---|
| White | 26,427 | 41.47% |
| Black or African American | 15,641 | 24.54% |
| Two or more races | 13,917 | 21.84% |
| Other race | 4,817 | 7.56% |
| Asian | 2,806 | 4.4% |
| Native American | 114 | 0.18% |
| Native Hawaiian or Pacific Islander | 8 | 0.01% |
Sanford 's average per capita income is $46,549. Household income levels show a median of $66,891. The poverty rate stands at 11.89%.
| Name | Median ↓ | Mean |
|---|---|---|
| Married Families | $100,491 | - |
| Families | $78,816 | $95,288 |
| Households | $66,891 | $83,106 |
| Non Families | $46,087 | $59,948 |
Average Income
Median Household Income
Poverty Rate