Sanford is a city located in Seminole County, Florida. Sanford has a 2025 population of 68,374. It is also the county seat of Seminole County. Sanford is currently growing at a rate of 2.17% annually and its population has increased by 11.91% since the most recent census, which recorded a population of 61,098 in 2020.
The average household income in Sanford is $81,996 with a poverty rate of 13.47%. The median age in Sanford is 36.8 years: 35.8 years for males, and 37.5 years for females.
Data after 2023 is projected based on recent change
The racial composition of Sanford includes 43.27% White, 26.32% Black or African American, 8.83% other race, 4.66% Asian, and smaller percentages for Native American, Native Hawaiian or Pacific Islander and multiracial populations.
White (43.3%)
Black or African American (26.3%)
Two or more races (16.8%)
Other race (8.8%)
Asian (4.7%)
Native American (0.1%)
Native Hawaiian or Pacific Islander (NaN%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 26,954 | 43.27% |
| Black or African American | 16,398 | 26.32% |
| Two or more races | 10,438 | 16.76% |
| Other race | 5,501 | 8.83% |
| Asian | 2,903 | 4.66% |
| Native American | 96 | 0.15% |
| Native Hawaiian or Pacific Islander | 2 | 0% |
Married
Widowed
Divorced
Separated
Never Married
Sanford's average per capita income is $44,389. Household income levels show a median of $62,877. The poverty rate stands at 13.47%.
Name | Median | Mean |
|---|---|---|
| Married Families | $97,408 | - |
| Families | $73,964 | $93,089 |
| Households | $62,877 | $81,996 |
| Non Families | $42,614 | $60,472 |
Average Income
Median Household Income
Poverty Rate