Sanibel is a city located in Lee County, Florida. Sanibel has a 2026 population of 6,342. Sanibel is currently declining at a rate of -0.13% annually and its population has decreased by -0.74% since the most recent census, which recorded a population of 6,389 in 2020.
The median household income in Sanibel is $108,644 with a poverty rate of 11.6%. The median age in Sanibel is 67.3 years: 68.4 years for males, and 64.7 years for females. For every 100 females there are 89.9 males.
Data after 2023 is projected based on recent change
Overall: 67.3 years
Female: 64.7 years
Male: 68.4 years
There are 6,077 adults, (3,522 of whom are seniors) in Sanibel.
Female: 3,379 (52.6%)
Male: 3,039 (47.4%)
The racial composition of Sanibel includes 94.11% White, and smaller percentages for Two or more races, other race, Black or African American, Asian, Native American and multiracial populations.
| Race | Population ↓ | Percentage (of total) |
|---|---|---|
| White | 6,040 | 94.11% |
| Two or more races | 171 | 2.66% |
| Other race | 104 | 1.62% |
| Black or African American | 46 | 0.72% |
| Asian | 43 | 0.67% |
| Native American | 14 | 0.22% |
Sanibel 's average per capita income is $49,510. Household income levels show a median of $108,644. The poverty rate stands at 11.6%.
| Name | Median ↓ | Mean |
|---|---|---|
| Married Families | $163,438 | - |
| Families | $155,962 | $248,072 |
| Households | $108,644 | $221,748 |
| Non Families | $44,888 | $144,208 |
Average Income
Median Household Income
Poverty Rate