Suez township is located in Mercer County, Illinois. Suez township has a 2026 population of 578. Suez township is currently declining at a rate of -1.03% annually and its population has decreased by -4.46% since the most recent census, which recorded a population of 605 in 2020.
The median household income in Suez township is $87,143 with a poverty rate of 3.91%. The median age in Suez township is 55.5 years: 57.6 years for males, and 52.4 years for females. For every 100 females there are 91.5 males.
Data after 2023 is projected based on recent change
Overall: 55.5 years
Female: 52.4 years
Male: 57.6 years
There are 588 adults, (199 of whom are seniors) in Suez township.
Female: 377 (52.2%)
Male: 345 (47.8%)
The racial composition of Suez township includes 90.58% White, 3.74% Asian, and smaller percentages for and multiracial populations.
| Race | Population ↓ | Percentage (of total) |
|---|---|---|
| White | 654 | 90.58% |
| Two or more races | 41 | 5.68% |
| Asian | 27 | 3.74% |
Suez township 's average per capita income is $58,000. Household income levels show a median of $87,143. The poverty rate stands at 3.91%.
| Name | Median ↓ | Mean |
|---|---|---|
| Married Families | $108,214 | - |
| Families | $97,159 | $119,774 |
| Households | $87,143 | $103,329 |
| Non Families | - | $32,364 |
Average Income
Median Household Income
Poverty Rate