Suez township is located in Mercer County, Illinois. Suez township has a 2026 population of 590. Suez township is currently declining at a rate of -1.01% annually and its population has decreased by -2.48% since the most recent census, which recorded a population of 605 in 2020.
The median household income in Suez township is $73,417 with a poverty rate of 3.82%. The median age in Suez township is 56.8 years: 57.5 years for males, and 56 years for females. For every 100 females there are 98.3 males.
Data after 2023 is projected based on recent change
The racial composition of Suez township includes 91.35% White, 3.37% Asian, and smaller percentages for and multiracial populations.
White (91.35%)
Two or more races (5.28%)
Asian (3.37%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 623 | 91.35% |
| Two or more races | 36 | 5.28% |
| Asian | 23 | 3.37% |
Married
Widowed
Divorced
Separated
Never Married
Suez township's average per capita income is $50,833. Household income levels show a median of $73,417. The poverty rate stands at 3.82%.
Name | Median | Mean |
|---|---|---|
| Married Families | $92,969 | - |
| Families | $84,219 | $110,708 |
| Households | $73,417 | $94,064 |
| Non Families | - | $35,356 |
Average Income
Median Household Income
Poverty Rate