Brown is located in Hendricks County, Indiana. Brown has a 2025 population of 15,635 . Brown is currently growing at a rate of 1.46% annually and its population has increased by 8.64% since the most recent census, which recorded a population of 14,391 in 2020.
The average household income in Brown is $173,482 with a poverty rate of 1.61%. The median age in Brown is 38.2 years: 37.3 years for males, and 38.5 years for females. For every 100 females there are 94.3 males.
Data after 2023 is projected based on recent change
The racial composition of Brown includes 85.87% White, 8.05% Black or African American, and smaller percentages for Two or more races, other race, Asian, Native Hawaiian or Pacific Islander and multiracial populations.
White (85.87%)
Black or African American (8.05%)
Two or more races (2.31%)
Other race (2.15%)
Asian (1.5%)
Native Hawaiian or Pacific Islander (0.12%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 12,560 | 85.87% |
| Black or African American | 1,177 | 8.05% |
| Two or more races | 338 | 2.31% |
| Other race | 314 | 2.15% |
| Asian | 219 | 1.5% |
| Native Hawaiian or Pacific Islander | 18 | 0.12% |
Married
Widowed
Divorced
Separated
Never Married
Brown's average per capita income is $73,237. Household income levels show a median of $139,212. The poverty rate stands at 1.61%.
Name | Median | Mean |
|---|---|---|
| Married Families | $156,302 | - |
| Families | $144,765 | $185,213 |
| Households | $139,212 | $173,482 |
| Non Families | $81,301 | $90,229 |
Average Income
Median Household Income
Poverty Rate