Jefferson is located in Elkhart County, Indiana. Jefferson has a 2025 population of 10,993. Jefferson is currently declining at a rate of -0.05% annually but its population has increased by 0.01% since the most recent census, which recorded a population of 10,992 in 2020.
The average household income in Jefferson is $128,278 with a poverty rate of 3.67%. The median age in Jefferson is 32.7 years: 33.6 years for males, and 32.2 years for females.
Data after 2023 is projected based on recent change
The racial composition of Jefferson includes 88.33% White, and smaller percentages for other race, Black or African American, Asian, Native American, Native Hawaiian or Pacific Islander and multiracial populations.
White (88.3%)
Two or more races (9.4%)
Other race (0.8%)
Black or African American (0.7%)
Asian (0.5%)
Native American (0.2%)
Native Hawaiian or Pacific Islander (0.1%)
Race | Population | Percentage (of total) |
---|---|---|
White | 9,708 | 88.33% |
Two or more races | 1,037 | 9.44% |
Other race | 87 | 0.79% |
Black or African American | 75 | 0.68% |
Asian | 53 | 0.48% |
Native American | 21 | 0.19% |
Native Hawaiian or Pacific Islander | 9 | 0.08% |
Married
Widowed
Divorced
Separated
Never Married
Jefferson's average per capita income is $53,141. Household income levels show a median of $112,566. The poverty rate stands at 3.67%.
Name | Median | Mean |
---|---|---|
Married Families | $124,602 | - |
Families | $114,414 | $132,723 |
Households | $112,566 | $128,278 |
Non Families | $80,179 | $86,459 |
Average Income
Median Household Income
Poverty Rate