Seymour is a city located in Jackson County, Indiana. Seymour has a 2025 population of 22,640 . Seymour is currently growing at a rate of 0.52% annually and its population has increased by 2.64% since the most recent census, which recorded a population of 22,058 in 2020.
The average household income in Seymour is $77,047 with a poverty rate of 14.42%. The median age in Seymour is 33.3 years: 29.4 years for males, and 37.4 years for females. For every 100 females there are 102.1 males.
Data after 2023 is projected based on recent change
The racial composition of Seymour includes 68.43% White, 8.72% other race, 4.24% Asian, and smaller percentages for Black or African American, Native American, Native Hawaiian or Pacific Islander and multiracial populations.
White (68.43%)
Two or more races (14.86%)
Other race (8.72%)
Asian (4.24%)
Black or African American (2.02%)
Native American (1.62%)
Native Hawaiian or Pacific Islander (0.1%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 14,737 | 68.43% |
| Two or more races | 3,201 | 14.86% |
| Other race | 1,877 | 8.72% |
| Asian | 914 | 4.24% |
| Black or African American | 436 | 2.02% |
| Native American | 349 | 1.62% |
| Native Hawaiian or Pacific Islander | 22 | 0.1% |
Married
Widowed
Divorced
Separated
Never Married
Seymour's average per capita income is $45,270. Household income levels show a median of $63,388. The poverty rate stands at 14.42%.
Name | Median | Mean |
|---|---|---|
| Married Families | $88,518 | - |
| Families | $74,211 | $87,686 |
| Households | $63,388 | $77,047 |
| Non Families | $38,029 | $51,366 |
Average Income
Median Household Income
Poverty Rate