Seymour is a city located in Jackson County, Indiana. Seymour has a 2026 population of 22,757. Seymour is currently growing at a rate of 0.52% annually and its population has increased by 3.17% since the most recent census, which recorded a population of 22,058 in 2020.
The median household income in Seymour is $64,426 with a poverty rate of 15.49%. The median age in Seymour is 33.3 years: 28.5 years for males, and 38.5 years for females. For every 100 females there are 108.6 males.
Data after 2023 is projected based on recent change
Overall: 33.3 years
Female: 38.5 years
Male: 28.5 years
There are 15,572 adults, (2,917 of whom are seniors) in Seymour.
Female: 10,725 (47.9%)
Male: 11,646 (52.1%)
The racial composition of Seymour includes 65.96% White, 7.48% other race, 4.43% Native American, 4.08% Asian, and smaller percentages for Black or African American and multiracial populations.
| Race | Population ↓ | Percentage (of total) |
|---|---|---|
| White | 14,757 | 65.96% |
| Two or more races | 3,798 | 16.98% |
| Other race | 1,674 | 7.48% |
| Native American | 990 | 4.43% |
| Asian | 913 | 4.08% |
| Black or African American | 239 | 1.07% |
Seymour 's average per capita income is $47,759. Household income levels show a median of $64,426. The poverty rate stands at 15.49%.
| Name | Median ↓ | Mean |
|---|---|---|
| Married Families | $91,940 | - |
| Families | $77,895 | $88,927 |
| Households | $64,426 | $75,584 |
| Non Families | $35,847 | $44,089 |
Average Income
Median Household Income
Poverty Rate