Dyersville is a city located in Dubuque County, Iowa. Dyersville has a 2025 population of 4,573 . Dyersville is currently growing at a rate of 0.31% annually and its population has increased by 1.62% since the most recent census, which recorded a population of 4,500 in 2020.
The average household income in Dyersville is $89,338 with a poverty rate of 4.53%. The median age in Dyersville is 44.3 years: 38.5 years for males, and 48.4 years for females. For every 100 females there are 94.9 males.
Data after 2023 is projected based on recent change
The racial composition of Dyersville includes 92.38% White, 4.48% other race, and smaller percentages for Two or more races, Black or African American and multiracial populations.
White (92.38%)
Other race (4.48%)
Two or more races (2.85%)
Black or African American (0.3%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 4,025 | 92.38% |
| Other race | 195 | 4.48% |
| Two or more races | 124 | 2.85% |
| Black or African American | 13 | 0.3% |
Married
Widowed
Divorced
Separated
Never Married
Dyersville's average per capita income is $49,145. Household income levels show a median of $72,768. The poverty rate stands at 4.53%.
Name | Median | Mean |
|---|---|---|
| Married Families | $100,375 | - |
| Families | $94,896 | $101,433 |
| Households | $72,768 | $89,338 |
| Non Families | $41,406 | $65,533 |
Average Income
Median Household Income
Poverty Rate