Hayesville is a city located in Keokuk County, Iowa. Hayesville has a 2025 population of 44. Hayesville is currently declining at a rate of 0% annually and its population has decreased by 0% since the most recent census, which recorded a population of 44 in 2020.
The average household income in Hayesville is $56,888 with a poverty rate of 35.48%.The median age in Hayesville is 68 years: 71.3 years for males, and 64.4 years for females.
Data after 2023 is projected based on recent change
The racial composition of Hayesville includes 100% White, and smaller percentages for and multiracial populations.
Race | Population | Percentage (of total) |
---|---|---|
White | 62 | 100% |
Married
Widowed
Divorced
Separated
Never Married
Hayesville's average per capita income is $31,250. Household income levels show a median of $43,750. The poverty rate stands at 35.48%.
Name | Median | Mean |
---|---|---|
Married Families | $101,500 | - |
Families | $101,250 | $92,747 |
Households | $43,750 | $56,888 |
Non Families | $27,708 | $25,247 |
Average Income
Median Household Income
Poverty Rate