Hayesville is a city located in Keokuk County, Iowa. Hayesville has a 2025 population of 42 . Hayesville is currently declining at a rate of -2.33% annually and its population has decreased by -4.55% since the most recent census, which recorded a population of 44 in 2020.
The average household income in Hayesville is $56,888 with a poverty rate of 35.48%. The median age in Hayesville is 68 years: 71.3 years for males, and 64.4 years for females. For every 100 females there are 87.9 males.
Data after 2023 is projected based on recent change
The racial composition of Hayesville includes 100% White, and smaller percentages for and multiracial populations.
White (100%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 62 | 100% |
Married
Widowed
Divorced
Separated
Never Married
Hayesville's average per capita income is $31,250. Household income levels show a median of $43,750. The poverty rate stands at 35.48%.
Name | Median | Mean |
|---|---|---|
| Married Families | $101,500 | - |
| Families | $101,250 | $92,747 |
| Households | $43,750 | $56,888 |
| Non Families | $27,708 | $25,247 |
Average Income
Median Household Income
Poverty Rate