Roseland

County:: Tangipahoa Parish
County Seat:: No
Area (mi²):: 2.076
State:: Louisiana

Roseland is a town located in Tangipahoa Parish, Louisiana. Roseland has a 2025 population of 895. Roseland is currently growing at a rate of 0.22% annually and its population has increased by 1.24% since the most recent census, which recorded a population of 884 in 2020.

The average household income in Roseland is $49,591 with a poverty rate of 53.51%.The median age in Roseland is 31.5 years: 26.3 years for males, and 40.6 years for females.

Demographics

The racial composition of Roseland includes 53.69% Black or African American, 44.44% White, and smaller percentages for Two or more races, Asian and multiracial populations.

Population by Race

Race	Population	Percentage (of total)
Black or African American	604	53.69%
White	500	44.44%
Two or more races	14	1.24%
Asian	7	0.62%

Roseland Marital Status

Married

Widowed

Divorced

Separated

Never Married

Economics and Income Statistics

Roseland's average per capita income is $33,101. Household income levels show a median of $46,003. The poverty rate stands at 53.51%.

Families: A family includes the owner or renter of the home along with everyone related to them - whether through birth, marriage, or adoption. This includes relatives like spouses, children, parents, siblings, grandparents, and any other family members.

Households: A household includes all the people who occupy a housing unit (such as a house or apartment) as their usual place of residence.

Non Families: A nonfamily household is either someone living alone or when the owner/renter lives with people they aren't related to, like roommates.

Name	Median	Mean
Married Families	$51,384	-
Families	$46,029	$51,206
Households	$46,003	$49,591
Non Families	-	$37,025

$33,101

Average Income

$46,003

Median Household Income

53.51%

Poverty Rate