Rocksbury township is located in Pennington County, Minnesota. Rocksbury township has a 2026 population of 1,050. Rocksbury township is currently declining at a rate of 0% annually and its population has decreased by -3.85% since the most recent census, which recorded a population of 1,092 in 2020.
The median household income in Rocksbury township is $110,144 with a poverty rate of 9.36%. The median age in Rocksbury township is 41.1 years: 44.5 years for males, and 39.3 years for females. For every 100 females there are 97.2 males.
Data after 2023 is projected based on recent change
The racial composition of Rocksbury township includes 88.89% White, 3.51% Asian, 3.09% other race, and smaller percentages for Native American and multiracial populations.
White (88.89%)
Two or more races (4.26%)
Asian (3.51%)
Other race (3.09%)
Native American (0.25%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 1,064 | 88.89% |
| Two or more races | 51 | 4.26% |
| Asian | 42 | 3.51% |
| Other race | 37 | 3.09% |
| Native American | 3 | 0.25% |
Married
Widowed
Divorced
Separated
Never Married
Rocksbury township's average per capita income is $51,484. Household income levels show a median of $110,144. The poverty rate stands at 9.36%.
Name | Median | Mean |
|---|---|---|
| Married Families | $115,179 | - |
| Families | $114,167 | $134,800 |
| Households | $110,144 | $114,335 |
| Non Families | - | $63,391 |
Average Income
Median Household Income
Poverty Rate