Jefferson is a village located in Ashtabula County, Ohio. Jefferson has a 2026 population of 3,173. It is also the county seat of Ashtabula County. Jefferson is currently declining at a rate of -0.22% annually and its population has decreased by -1.4% since the most recent census, which recorded a population of 3,218 in 2020.
The median household income in Jefferson is $53,333 with a poverty rate of 6.51%. The median age in Jefferson is 49.3 years: 33.4 years for males, and 55.8 years for females. For every 100 females there are 83.1 males.
Data after 2023 is projected based on recent change
Overall: 49.3 years
Female: 55.8 years
Male: 33.4 years
There are 2,722 adults, (961 of whom are seniors) in Jefferson.
Female: 1,924 (54.6%)
Male: 1,598 (45.4%)
The racial composition of Jefferson includes 92.05% White, and smaller percentages for other race, Native Hawaiian or Pacific Islander, Black or African American and multiracial populations.
| Race | Population ↓ | Percentage (of total) |
|---|---|---|
| White | 3,242 | 92.05% |
| Two or more races | 188 | 5.34% |
| Other race | 50 | 1.42% |
| Native Hawaiian or Pacific Islander | 24 | 0.68% |
| Black or African American | 18 | 0.51% |
Jefferson 's average per capita income is $48,613. Household income levels show a median of $53,333. The poverty rate stands at 6.51%.
| Name | Median ↓ | Mean |
|---|---|---|
| Married Families | $95,234 | - |
| Families | $83,542 | $97,518 |
| Households | $53,333 | $68,204 |
| Non Families | $35,174 | $44,125 |
Average Income
Median Household Income
Poverty Rate