Jefferson is a village located in Ashtabula County, Ohio. Jefferson has a 2025 population of 3,180 . It is also the county seat of Ashtabula County . Jefferson is currently declining at a rate of -0.25% annually and its population has decreased by -1.18% since the most recent census, which recorded a population of 3,218 in 2020.
The average household income in Jefferson is $64,131 with a poverty rate of 12.55%. The median age in Jefferson is 55.2 years: 33.7 years for males, and 63.2 years for females. For every 100 females there are 86.6 males.
Data after 2023 is projected based on recent change
The racial composition of Jefferson includes 92.08% White, and smaller percentages for other race, Native Hawaiian or Pacific Islander, Black or African American and multiracial populations.
White (92.08%)
Two or more races (4%)
Other race (2.15%)
Native Hawaiian or Pacific Islander (1.02%)
Black or African American (0.75%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 3,082 | 92.08% |
| Two or more races | 134 | 4% |
| Other race | 72 | 2.15% |
| Native Hawaiian or Pacific Islander | 34 | 1.02% |
| Black or African American | 25 | 0.75% |
Married
Widowed
Divorced
Separated
Never Married
Jefferson's average per capita income is $50,920. Household income levels show a median of $47,469. The poverty rate stands at 12.55%.
Name | Median | Mean |
|---|---|---|
| Married Families | $88,965 | - |
| Families | $88,164 | $91,798 |
| Households | $47,469 | $64,131 |
| Non Families | $29,318 | $40,846 |
Average Income
Median Household Income
Poverty Rate