Jefferson is located in Ashtabula County, Ohio. Jefferson has a 2025 population of 1,471 . It is also the county seat of Ashtabula County . Jefferson is currently growing at a rate of 0.27% annually and its population has increased by 1.45% since the most recent census, which recorded a population of 1,450 in 2020.
The average household income in Jefferson is $74,041 with a poverty rate of 17.4%. The median age in Jefferson is 42.4 years: 43.2 years for males, and 41 years for females. For every 100 females there are 87.0 males.
Data after 2023 is projected based on recent change
The racial composition of Jefferson includes 88.78% White, 8.57% Asian, and smaller percentages for Two or more races, other race and multiracial populations.
White (88.78%)
Asian (8.57%)
Two or more races (2.11%)
Other race (0.54%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 1,305 | 88.78% |
| Asian | 126 | 8.57% |
| Two or more races | 31 | 2.11% |
| Other race | 8 | 0.54% |
Married
Widowed
Divorced
Separated
Never Married
Jefferson's average per capita income is $38,191. Household income levels show a median of $58,375. The poverty rate stands at 17.4%.
Name | Median | Mean |
|---|---|---|
| Married Families | $87,552 | - |
| Families | $72,250 | $84,920 |
| Households | $58,375 | $74,041 |
| Non Families | $25,000 | $39,097 |
Average Income
Median Household Income
Poverty Rate