Jefferson is located in Ashtabula County, Ohio. Jefferson has a 2025 population of 16,556 . It is also the county seat of Ashtabula County . Jefferson is currently growing at a rate of 2.3% annually and its population has increased by 14.21% since the most recent census, which recorded a population of 14,496 in 2020.
The average household income in Jefferson is $191,695 with a poverty rate of 2.63%. The median age in Jefferson is 39 years: 40.3 years for males, and 36.4 years for females. For every 100 females there are 90.0 males.
Data after 2023 is projected based on recent change
The racial composition of Jefferson includes 63.05% White, 16.62% Black or African American, 11.66% Asian, and smaller percentages for other race, Native American and multiracial populations.
White (63.05%)
Black or African American (16.62%)
Asian (11.66%)
Two or more races (7.17%)
Other race (1.28%)
Native American (0.23%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 8,936 | 63.05% |
| Black or African American | 2,355 | 16.62% |
| Asian | 1,652 | 11.66% |
| Two or more races | 1,016 | 7.17% |
| Other race | 181 | 1.28% |
| Native American | 33 | 0.23% |
Married
Widowed
Divorced
Separated
Never Married
Jefferson's average per capita income is $75,406. Household income levels show a median of $126,622. The poverty rate stands at 2.63%.
Name | Median | Mean |
|---|---|---|
| Married Families | $161,932 | - |
| Families | $152,618 | $218,851 |
| Households | $126,622 | $191,695 |
| Non Families | $65,065 | $106,988 |
Average Income
Median Household Income
Poverty Rate