Jefferson is located in Ashtabula County, Ohio. Jefferson has a 2025 population of 8,552 . It is also the county seat of Ashtabula County . Jefferson is currently growing at a rate of 5.93% annually and its population has increased by 18.33% since the most recent census, which recorded a population of 7,227 in 2020.
The average household income in Jefferson is $91,135 with a poverty rate of 8.5%. The median age in Jefferson is 45.1 years: 44.7 years for males, and 45.9 years for females. For every 100 females there are 95.9 males.
Data after 2023 is projected based on recent change
The racial composition of Jefferson includes 95.23% White, and smaller percentages for Black or African American, Asian, other race, Native American and multiracial populations.
White (95.23%)
Two or more races (4.33%)
Black or African American (0.15%)
Asian (0.12%)
Other race (0.1%)
Native American (0.07%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 6,974 | 95.23% |
| Two or more races | 317 | 4.33% |
| Black or African American | 11 | 0.15% |
| Asian | 9 | 0.12% |
| Other race | 7 | 0.1% |
| Native American | 5 | 0.07% |
Married
Widowed
Divorced
Separated
Never Married
Jefferson's average per capita income is $50,641. Household income levels show a median of $78,663. The poverty rate stands at 8.5%.
Name | Median | Mean |
|---|---|---|
| Married Families | $107,059 | - |
| Families | $93,005 | $100,388 |
| Households | $78,663 | $91,135 |
| Non Families | $49,482 | $68,222 |
Average Income
Median Household Income
Poverty Rate