Jefferson is located in Ashtabula County, Ohio. Jefferson has a 2025 population of 8,203. It is also the county seat of Ashtabula County. Jefferson is currently growing at a rate of 3.91% annually and its population has increased by 13.52% since the most recent census, which recorded a population of 7,226 in 2020.
The average household income in Jefferson is $91,135 with a poverty rate of 8.5%. The median age in Jefferson is 45.1 years: 44.7 years for males, and 45.9 years for females.
Data after 2023 is projected based on recent change
The racial composition of Jefferson includes 95.23% White, and smaller percentages for Black or African American, Asian, other race, Native American and multiracial populations.
White (95.2%)
Two or more races (4.3%)
Black or African American (0.1%)
Asian (0.1%)
Other race (0.1%)
Native American (0.1%)
Race | Population | Percentage (of total) |
---|---|---|
White | 6,974 | 95.23% |
Two or more races | 317 | 4.33% |
Black or African American | 11 | 0.15% |
Asian | 9 | 0.12% |
Other race | 7 | 0.1% |
Native American | 5 | 0.07% |
Married
Widowed
Divorced
Separated
Never Married
Jefferson's average per capita income is $50,641. Household income levels show a median of $78,663. The poverty rate stands at 8.5%.
Name | Median | Mean |
---|---|---|
Married Families | $107,059 | - |
Families | $93,005 | $100,388 |
Households | $78,663 | $91,135 |
Non Families | $49,482 | $68,222 |
Average Income
Median Household Income
Poverty Rate