Jefferson is located in Ashtabula County, Ohio. Jefferson has a 2025 population of 5,978. It is also the county seat of Ashtabula County. Jefferson is currently growing at a rate of 0.22% annually and its population has increased by 1.91% since the most recent census, which recorded a population of 5,866 in 2020.
The average household income in Jefferson is $71,018 with a poverty rate of 15.23%. The median age in Jefferson is 46.4 years: 46.8 years for males, and 45.4 years for females.
Data after 2023 is projected based on recent change
The racial composition of Jefferson includes 56.31% Black or African American, 36.54% White, and smaller percentages for other race, Asian and multiracial populations.
Black or African American (56.3%)
White (36.5%)
Two or more races (5.6%)
Other race (1.5%)
Asian (0.0%)
Race | Population | Percentage (of total) |
|---|---|---|
| Black or African American | 3,316 | 56.31% |
| White | 2,152 | 36.54% |
| Two or more races | 332 | 5.64% |
| Other race | 88 | 1.49% |
| Asian | 1 | 0.02% |
Married
Widowed
Divorced
Separated
Never Married
Jefferson's average per capita income is $45,603. Household income levels show a median of $60,680. The poverty rate stands at 15.23%.
Name | Median | Mean |
|---|---|---|
| Married Families | $100,291 | - |
| Families | $83,015 | $87,818 |
| Households | $60,680 | $71,018 |
| Non Families | $28,750 | $45,994 |
Average Income
Median Household Income
Poverty Rate