Port Jefferson is a village located in Shelby County, Ohio. Port Jefferson has a 2026 population of 299. Port Jefferson is currently declining at a rate of -0.33% annually and its population has decreased by -2.92% since the most recent census, which recorded a population of 308 in 2020.
The median household income in Port Jefferson is $57,083 with a poverty rate of 13.38%. The median age in Port Jefferson is 51.1 years: 51.3 years for males, and 49 years for females. For every 100 females there are 98.7 males.
Data after 2023 is projected based on recent change
Overall: 51.1 years
Female: 49 years
Male: 51.3 years
There are 272 adults, (61 of whom are seniors) in Port Jefferson.
Female: 154 (50.3%)
Male: 152 (49.7%)
The racial composition of Port Jefferson includes 97.71% White, and smaller percentages for Two or more races and multiracial populations.
| Race | Population ↓ | Percentage (of total) |
|---|---|---|
| White | 299 | 97.71% |
| Two or more races | 7 | 2.29% |
Port Jefferson 's average per capita income is $44,412. Household income levels show a median of $57,083. The poverty rate stands at 13.38%.
| Name | Median ↓ | Mean |
|---|---|---|
| Married Families | $80,000 | - |
| Families | $73,750 | $75,513 |
| Households | $57,083 | $65,008 |
| Non Families | $42,917 | $45,787 |
Average Income
Median Household Income
Poverty Rate