Port Jefferson is a village located in Shelby County, Ohio. Port Jefferson has a 2025 population of 300 . Port Jefferson is currently declining at a rate of -0.66% annually and its population has decreased by -2.6% since the most recent census, which recorded a population of 308 in 2020.
The average household income in Port Jefferson is $63,312 with a poverty rate of 13.14%. The median age in Port Jefferson is 42.9 years: 45.3 years for males, and 41.4 years for females. For every 100 females there are 79.6 males.
Data after 2023 is projected based on recent change
The racial composition of Port Jefferson includes 95.57% White, and smaller percentages for and multiracial populations.
White (95.57%)
Two or more races (4.43%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 345 | 95.57% |
| Two or more races | 16 | 4.43% |
Married
Widowed
Divorced
Separated
Never Married
Port Jefferson's average per capita income is $41,172. Household income levels show a median of $50,714. The poverty rate stands at 13.14%.
Name | Median | Mean |
|---|---|---|
| Married Families | $76,625 | - |
| Families | $66,563 | $72,376 |
| Households | $50,714 | $63,312 |
| Non Families | $22,656 | $50,221 |
Average Income
Median Household Income
Poverty Rate