Selinsgrove is a borough located in Snyder County, Pennsylvania. Selinsgrove has a 2025 population of 5,462. Selinsgrove is currently declining at a rate of -0.91% annually and its population has decreased by -4.38% since the most recent census, which recorded a population of 5,712 in 2020.
The average household income in Selinsgrove is $70,262 with a poverty rate of 7.74%.The median age in Selinsgrove is 24.4 years: 26.2 years for males, and 23.2 years for females.
Data after 2023 is projected based on recent change
The racial composition of Selinsgrove includes 87.64% White, 4.23% Black or African American, and smaller percentages for Native Hawaiian or Pacific Islander, Asian, other race, Native American and multiracial populations.
Race | Population | Percentage (of total) |
---|---|---|
White | 4,956 | 87.64% |
Two or more races | 262 | 4.63% |
Black or African American | 239 | 4.23% |
Native Hawaiian or Pacific Islander | 80 | 1.41% |
Asian | 57 | 1.01% |
Other race | 57 | 1.01% |
Native American | 4 | 0.07% |
Married
Widowed
Divorced
Separated
Never Married
Selinsgrove's average per capita income is $42,857. Household income levels show a median of $58,484. The poverty rate stands at 7.74%.
Name | Median | Mean |
---|---|---|
Married Families | $105,699 | - |
Families | $88,828 | $95,100 |
Households | $58,484 | $70,262 |
Non Families | $36,836 | $50,382 |
Average Income
Median Household Income
Poverty Rate