Selinsgrove is a borough located in Snyder County, Pennsylvania. Selinsgrove has a 2026 population of 5,396. Selinsgrove is currently declining at a rate of -0.95% annually and its population has decreased by -5.5% since the most recent census, which recorded a population of 5,710 in 2020.
The median household income in Selinsgrove is $65,650 with a poverty rate of 5.08%. The median age in Selinsgrove is 22.8 years: 23 years for males, and 22.3 years for females. For every 100 females there are 96.5 males.
Data after 2023 is projected based on recent change
Overall: 22.8 years
Female: 22.3 years
Male: 23 years
There are 5,173 adults, (1,017 of whom are seniors) in Selinsgrove.
Female: 2,847 (50.9%)
Male: 2,746 (49.1%)
The racial composition of Selinsgrove includes 87.04% White, 3.84% Black or African American, and smaller percentages for Native Hawaiian or Pacific Islander, Asian, other race and multiracial populations.
| Race | Population ↓ | Percentage (of total) |
|---|---|---|
| White | 4,868 | 87.04% |
| Two or more races | 303 | 5.42% |
| Black or African American | 215 | 3.84% |
| Native Hawaiian or Pacific Islander | 99 | 1.77% |
| Asian | 98 | 1.75% |
| Other race | 10 | 0.18% |
Selinsgrove 's average per capita income is $42,603. Household income levels show a median of $65,650. The poverty rate stands at 5.08%.
| Name | Median ↓ | Mean |
|---|---|---|
| Married Families | $109,449 | - |
| Families | $100,000 | $107,457 |
| Households | $65,650 | $77,584 |
| Non Families | $39,948 | $52,287 |
Average Income
Median Household Income
Poverty Rate