Mendon is a city located in Cache County, Utah. Mendon has a 2025 population of 1,340. Mendon is currently declining at a rate of 0% annually and its population has increased by 0.15% since the most recent census, which recorded a population of 1,338 in 2020.
The average household income in Mendon is $149,458 with a poverty rate of 0%. The median age in Mendon is 35.4 years: 34.8 years for males, and 35.7 years for females.
Data after 2023 is projected based on recent change
The racial composition of Mendon includes 93.36% White, and smaller percentages for other race, Black or African American and multiracial populations.
White (93.4%)
Two or more races (4.4%)
Other race (1.2%)
Black or African American (1.0%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 1,350 | 93.36% |
| Two or more races | 63 | 4.36% |
| Other race | 18 | 1.24% |
| Black or African American | 15 | 1.04% |
Married
Widowed
Divorced
Separated
Never Married
Mendon's average per capita income is $63,281. Household income levels show a median of $141,563. The poverty rate stands at 0%.
Name | Median | Mean |
|---|---|---|
| Married Families | $154,231 | - |
| Families | $153,654 | $169,823 |
| Households | $141,563 | $149,458 |
| Non Families | $45,263 | $48,735 |
Average Income
Median Household Income
Poverty Rate