La Crosse is a town located in Alachua County, Florida. La Crosse has a 2025 population of 326 . La Crosse is currently growing at a rate of 0.62% annually and its population has increased by 3.82% since the most recent census, which recorded a population of 314 in 2020.
The average household income in La Crosse is $93,543 with a poverty rate of 4.85%. The median age in La Crosse is 50.2 years: 44.8 years for males, and 50.3 years for females. For every 100 females there are 74.6 males.
Data after 2023 is projected based on recent change
The racial composition of La Crosse includes 90.31% White, 6.61% Black or African American, and smaller percentages for Two or more races, Asian and multiracial populations.
White (90.31%)
Black or African American (6.61%)
Two or more races (2.64%)
Asian (0.44%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 205 | 90.31% |
| Black or African American | 15 | 6.61% |
| Two or more races | 6 | 2.64% |
| Asian | 1 | 0.44% |
Married
Widowed
Divorced
Separated
Never Married
La Crosse's average per capita income is $53,750. Household income levels show a median of $88,819. The poverty rate stands at 4.85%.
Name | Median | Mean |
|---|---|---|
| Families | $89,167 | $97,280 |
| Households | $88,819 | $93,543 |
| Married Families | $71,964 | - |
| Non Families | - | $26,660 |
Average Income
Median Household Income
Poverty Rate