Harlan township is located in Shelby County, Iowa Iowa. Unfortunately, the data for this location is currently limited or unavailable.
The median household income in Harlan township is $59,167 with a poverty rate of 4.05%. The median age in Harlan township is 50.6 years: 50.5 years for males, and 51.1 years for females. For every 100 females there are 91.5 males.
No data available.
The racial composition of Harlan township includes 98.3% White, and smaller percentages for Two or more races, Black or African American and multiracial populations.
White (98.3%)
Two or more races (1.31%)
Black or African American (0.39%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 753 | 98.3% |
| Two or more races | 10 | 1.31% |
| Black or African American | 3 | 0.39% |
Married
Widowed
Divorced
Separated
Never Married
Harlan township's average per capita income is $48,672. Household income levels show a median of $59,167. The poverty rate stands at 4.05%.
Name | Median | Mean |
|---|---|---|
| Married Families | $101,563 | - |
| Families | $91,944 | $107,831 |
| Households | $59,167 | $85,665 |
| Non Families | $30,455 | $44,097 |
Average Income
Median Household Income
Poverty Rate