Harlan township

County:: Shelby County
County Seat:: No
Area (mi²):: 30.999
State:: Iowa

Harlan township is located in Shelby County, Iowa. Harlan township has a 2025 population of 252. Harlan township is currently declining at a rate of 0% annually and its population has decreased by 0% since the most recent census, which recorded a population of 0 in 2020.

The average household income in Harlan township is $91,568 with a poverty rate of 2.78%.The median age in Harlan township is 53.7 years: 53.9 years for males, and 53.3 years for females.

Demographics

The racial composition of Harlan township includes 98.81% White, and smaller percentages for Two or more races and multiracial populations.

Population by Race

Race	Population	Percentage (of total)
White	249	98.81%
Two or more races	3	1.19%

Harlan township Marital Status

Married

Widowed

Divorced

Separated

Never Married

Economics and Income Statistics

Harlan township's average per capita income is $54,250. Household income levels show a median of $77,031. The poverty rate stands at 2.78%.

Families: A family includes the owner or renter of the home along with everyone related to them - whether through birth, marriage, or adoption. This includes relatives like spouses, children, parents, siblings, grandparents, and any other family members.

Households: A household includes all the people who occupy a housing unit (such as a house or apartment) as their usual place of residence.

Non Families: A nonfamily household is either someone living alone or when the owner/renter lives with people they aren't related to, like roommates.

Name	Median	Mean
Married Families	$118,125	-
Families	$115,833	$104,907
Households	$77,031	$91,568
Non Families	$63,750	$54,561

$54,250

Average Income

$77,031

Median Household Income

2.78%

Poverty Rate