Harlan township is located in Shelby County, Iowa Iowa. Unfortunately, the data for this location is currently limited or unavailable.
The median household income in Harlan township is $103,750 with a poverty rate of 2.27%. The median age in Harlan township is 46.8 years: 50.3 years for males, and 46.6 years for females. For every 100 females there are 84.8 males.
The racial composition of Harlan township includes 98.58% White, and smaller percentages for Two or more races and multiracial populations.
| Race | Population ↓ | Percentage (of total) |
|---|---|---|
| White | 348 | 98.58% |
| Two or more races | 5 | 1.42% |
Harlan township 's average per capita income is $65,577. Household income levels show a median of $103,750. The poverty rate stands at 2.27%.
| Name | Median ↓ | Mean |
|---|---|---|
| Married Families | $128,750 | - |
| Families | $121,875 | $127,732 |
| Households | $103,750 | $111,691 |
| Non Families | $52,917 | $47,010 |
Average Income
Median Household Income
Poverty Rate