Oran township is located in Fayette County, Iowa Iowa. Unfortunately, the data for this location is currently limited or unavailable.
The median household income in Oran township is $104,167 with a poverty rate of 2.14%. The median age in Oran township is 52.5 years: 52.6 years for males, and 52.1 years for females. For every 100 females there are 128.3 males.
The racial composition of Oran township includes 83.88% White, and smaller percentages for and multiracial populations.
| Race | Population ↓ | Percentage (of total) |
|---|---|---|
| White | 588 | 83.88% |
| Two or more races | 113 | 16.12% |
Oran township 's average per capita income is $51,544. Household income levels show a median of $104,167. The poverty rate stands at 2.14%.
| Name | Median ↓ | Mean |
|---|---|---|
| Married Families | $115,875 | - |
| Families | $108,906 | $136,215 |
| Households | $104,167 | $118,820 |
| Non Families | $50,703 | $60,134 |
Average Income
Median Household Income
Poverty Rate