Oran township is located in Fayette County, Iowa Iowa. Unfortunately, the data for this location is currently limited or unavailable.
The median household income in Oran township is $105,964 with a poverty rate of 0.8%. The median age in Oran township is 52.5 years: 52.1 years for males, and 53.9 years for females. For every 100 females there are 131.1 males.
No data available.
The racial composition of Oran township includes 86.99% White, and smaller percentages for and multiracial populations.
White (86.99%)
Two or more races (13.01%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 762 | 86.99% |
| Two or more races | 114 | 13.01% |
Married
Widowed
Divorced
Separated
Never Married
Oran township's average per capita income is $50,750. Household income levels show a median of $105,964. The poverty rate stands at 0.8%.
Name | Median | Mean |
|---|---|---|
| Married Families | $114,632 | - |
| Families | $108,750 | $124,828 |
| Households | $105,964 | $114,339 |
| Non Families | $48,696 | $60,164 |
Average Income
Median Household Income
Poverty Rate