Searsboro is a city located in Poweshiek County, Iowa. Searsboro has a 2026 population of 128. Searsboro is currently declining at a rate of 0% annually and its population has decreased by -1.54% since the most recent census, which recorded a population of 130 in 2020.
The median household income in Searsboro is $66,250 with a poverty rate of 17.43%. The median age in Searsboro is 52.8 years: 49.5 years for males, and 53.5 years for females. For every 100 females there are 109.6 males.
Data after 2023 is projected based on recent change
Overall: 52.8 years
Female: 53.5 years
Male: 49.5 years
There are 87 adults, (21 of whom are seniors) in Searsboro.
Female: 52 (47.7%)
Male: 57 (52.3%)
The racial composition of Searsboro includes 98.17% White, and smaller percentages for Black or African American, Two or more races and multiracial populations.
| Race | Population ↓ | Percentage (of total) |
|---|---|---|
| White | 107 | 98.17% |
| Black or African American | 1 | 0.92% |
| Two or more races | 1 | 0.92% |
Searsboro 's average per capita income is $43,750. Household income levels show a median of $66,250. The poverty rate stands at 17.43%.
| Name | Median ↓ | Mean |
|---|---|---|
| Married Families | $92,500 | - |
| Families | $78,750 | $75,521 |
| Households | $66,250 | $75,007 |
| Non Families | $54,375 | $74,047 |
Average Income
Median Household Income
Poverty Rate