Searsboro

County:: Poweshiek County
County Seat:: No
Area (mi²):: 0.451
State:: Iowa

Searsboro is a city located in Poweshiek County, Iowa. Searsboro has a 2025 population of 125. Searsboro is currently declining at a rate of -0.79% annually and its population has decreased by -3.1% since the most recent census, which recorded a population of 129 in 2020.

The average household income in Searsboro is $62,089 with a poverty rate of 20.83%.The median age in Searsboro is 47 years: 48.3 years for males, and 40.3 years for females.

Demographics

The racial composition of Searsboro includes 98.33% White, and smaller percentages for Black or African American, Two or more races and multiracial populations.

Population by Race

Race	Population	Percentage (of total)
White	118	98.33%
Black or African American	1	0.83%
Two or more races	1	0.83%

Searsboro Marital Status

Married

Widowed

Divorced

Separated

Never Married

Economics and Income Statistics

Searsboro's average per capita income is $35,500. Household income levels show a median of $50,625. The poverty rate stands at 20.83%.

Families: A family includes the owner or renter of the home along with everyone related to them - whether through birth, marriage, or adoption. This includes relatives like spouses, children, parents, siblings, grandparents, and any other family members.

Households: A household includes all the people who occupy a housing unit (such as a house or apartment) as their usual place of residence.

Non Families: A nonfamily household is either someone living alone or when the owner/renter lives with people they aren't related to, like roommates.

Name	Median	Mean
Married Families	$60,000	-
Families	$51,250	$58,747
Households	$50,625	$62,089
Non Families	-	$70,315

$35,500

Average Income

$50,625

Median Household Income

20.83%

Poverty Rate