Searsboro is a city located in Poweshiek County, Iowa. Searsboro has a 2025 population of 125. Searsboro is currently declining at a rate of -0.79% annually and its population has decreased by -3.1% since the most recent census, which recorded a population of 129 in 2020.
The average household income in Searsboro is $62,089 with a poverty rate of 20.83%.The median age in Searsboro is 47 years: 48.3 years for males, and 40.3 years for females.
Data after 2023 is projected based on recent change
The racial composition of Searsboro includes 98.33% White, and smaller percentages for Black or African American, Two or more races and multiracial populations.
Race | Population | Percentage (of total) |
---|---|---|
White | 118 | 98.33% |
Black or African American | 1 | 0.83% |
Two or more races | 1 | 0.83% |
Married
Widowed
Divorced
Separated
Never Married
Searsboro's average per capita income is $35,500. Household income levels show a median of $50,625. The poverty rate stands at 20.83%.
Name | Median | Mean |
---|---|---|
Married Families | $60,000 | - |
Families | $51,250 | $58,747 |
Households | $50,625 | $62,089 |
Non Families | - | $70,315 |
Average Income
Median Household Income
Poverty Rate