Seymour Flag

Seymour

County:
Wayne County
County Seat:
No
Area (mi²):
2.392
State:
Iowa

Seymour is a city located in Wayne County, Iowa. Seymour has a 2026 population of 651. Seymour is currently growing at a rate of 0.46% annually and its population has increased by 2.36% since the most recent census, which recorded a population of 636 in 2020.

The median household income in Seymour is $46,071 with a poverty rate of 13.47%. The median age in Seymour is 44.5 years: 33.3 years for males, and 51.9 years for females. For every 100 females there are 99.3 males.

651
Total Population
272
Density (mi²)
3 0.46%
Growth

Seymour Population

Demographics

Economics and Income Statistics

Sources

  1. US Census State Population Estimates - Most recent state estimates from the Census Bureau's Population Estimates Program
  2. US Census County Population Estimates - Most recent county estimates from the Census Bureau's Population Estimates Program
  3. American Community Survey (2009 - 2013)
  4. Census QuickFacts
  5. Historical Populations of States and Counties (1790 - 1990)