Severn township is located in Stutsman County, North Dakota. Severn township has a 2026 population of 54. Severn township is currently declining at a rate of 0% annually and its population has decreased by -1.82% since the most recent census, which recorded a population of 55 in 2020.
The median household income in Severn township is $98,611 with a poverty rate of 0%. The median age in Severn township is 56.8 years: 67.6 years for males, and 45.5 years for females. For every 100 females there are 58.3 males.
Data after 2023 is projected based on recent change
The racial composition of Severn township includes 100% White, and smaller percentages for and multiracial populations.
White (100%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 38 | 100% |
Married
Widowed
Divorced
Separated
Never Married
Severn township's average per capita income is $31,250. Household income levels show a median of $98,611. The poverty rate stands at 0%.
Name | Median | Mean |
|---|---|---|
| Households | $98,611 | $88,457 |
| Families | $98,611 | $88,457 |
| Married Families | $98,611 | - |
| Non Families | - | - |
Average Income
Median Household Income
Poverty Rate