Sioux township is located in McKenzie County, North Dakota. Sioux township has a 2025 population of 168. Sioux township is currently growing at a rate of 3.7% annually and its population has increased by 4.35% since the most recent census, which recorded a population of 161 in 2020.
The average household income in Sioux township is $91,159 with a poverty rate of 4.02%.The median age in Sioux township is 41.3 years: 42 years for males, and 34.4 years for females.
Data after 2023 is projected based on recent change
The racial composition of Sioux township includes 77.11% White, and smaller percentages for Native American, Asian and multiracial populations.
Race | Population | Percentage (of total) |
---|---|---|
White | 192 | 77.11% |
Two or more races | 49 | 19.68% |
Native American | 7 | 2.81% |
Asian | 1 | 0.4% |
Married
Widowed
Divorced
Separated
Never Married
Sioux township's average per capita income is $56,912. Household income levels show a median of $56,029. The poverty rate stands at 4.02%.
Name | Median | Mean |
---|---|---|
Families | $89,375 | $123,048 |
Married Families | $89,375 | - |
Households | $56,029 | $91,159 |
Non Families | $45,966 | $51,459 |
Average Income
Median Household Income
Poverty Rate