Sioux township is located in McKenzie County, North Dakota. Sioux township has a 2026 population of 164. Sioux township is currently growing at a rate of 4.46% annually and its population has increased by 1.23% since the most recent census, which recorded a population of 162 in 2020.
The median household income in Sioux township is $56,029 with a poverty rate of 4.02%. The median age in Sioux township is 41.3 years: 42 years for males, and 34.4 years for females. For every 100 females there are 97.6 males.
Data after 2023 is projected based on recent change
The racial composition of Sioux township includes 77.11% White, and smaller percentages for Native American, Asian and multiracial populations.
White (77.11%)
Two or more races (19.68%)
Native American (2.81%)
Asian (0.4%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 192 | 77.11% |
| Two or more races | 49 | 19.68% |
| Native American | 7 | 2.81% |
| Asian | 1 | 0.4% |
Married
Widowed
Divorced
Separated
Never Married
Sioux township's average per capita income is $56,912. Household income levels show a median of $56,029. The poverty rate stands at 4.02%.
Name | Median | Mean |
|---|---|---|
| Families | $89,375 | $123,048 |
| Married Families | $89,375 | - |
| Households | $56,029 | $91,159 |
| Non Families | $45,966 | $51,459 |
Average Income
Median Household Income
Poverty Rate