Sioux township is located in McKenzie County, North Dakota. Sioux township has a 2026 population of 178. Sioux township is currently growing at a rate of 4.09% annually and its population has increased by 9.88% since the most recent census, which recorded a population of 162 in 2020.
The median household income in Sioux township is $58,818 with a poverty rate of 6.79%. The median age in Sioux township is 43.2 years: 50.5 years for males, and 34.9 years for females. For every 100 females there are 84.2 males.
Data after 2023 is projected based on recent change
Overall: 43.2 years
Female: 34.9 years
Male: 50.5 years
There are 167 adults, (59 of whom are seniors) in Sioux township.
Female: 120 (54.3%)
Male: 101 (45.7%)
The racial composition of Sioux township includes 73.3% White, 3.17% Native American, and smaller percentages for and multiracial populations.
| Race | Population ↓ | Percentage (of total) |
|---|---|---|
| White | 162 | 73.3% |
| Two or more races | 52 | 23.53% |
| Native American | 7 | 3.17% |
Sioux township 's average per capita income is $58,412. Household income levels show a median of $58,818. The poverty rate stands at 6.79%.
| Name | Median ↓ | Mean |
|---|---|---|
| Households | $58,818 | $95,119 |
| Non Families | $45,250 | $55,626 |
| Families | - | $118,321 |
| Married Families | - | - |
Average Income
Median Household Income
Poverty Rate