Jefferson is located in Ashtabula County, Ohio. Jefferson has a 2025 population of 3,227 . It is also the county seat of Ashtabula County . Jefferson is currently growing at a rate of 0.53% annually and its population has decreased by 0% since the most recent census, which recorded a population of 3,227 in 2020.
The average household income in Jefferson is $77,350 with a poverty rate of 11.75%. The median age in Jefferson is 39.8 years: 39.4 years for males, and 40.8 years for females. For every 100 females there are 98.8 males.
Data after 2023 is projected based on recent change
The racial composition of Jefferson includes 93.34% White, and smaller percentages for Black or African American, Asian, Native Hawaiian or Pacific Islander and multiracial populations.
White (93.34%)
Two or more races (3.83%)
Black or African American (1.99%)
Asian (0.72%)
Native Hawaiian or Pacific Islander (0.12%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 3,000 | 93.34% |
| Two or more races | 123 | 3.83% |
| Black or African American | 64 | 1.99% |
| Asian | 23 | 0.72% |
| Native Hawaiian or Pacific Islander | 4 | 0.12% |
Married
Widowed
Divorced
Separated
Never Married
Jefferson's average per capita income is $47,059. Household income levels show a median of $73,600. The poverty rate stands at 11.75%.
Name | Median | Mean |
|---|---|---|
| Married Families | $100,058 | - |
| Families | $97,545 | $90,432 |
| Households | $73,600 | $77,350 |
| Non Families | $30,060 | $41,669 |
Average Income
Median Household Income
Poverty Rate