Seville is a village located in Medina County, Ohio. Seville has a 2025 population of 2,385 . Seville is currently growing at a rate of 0.42% annually and its population has increased by 2.14% since the most recent census, which recorded a population of 2,335 in 2020.
The average household income in Seville is $83,681 with a poverty rate of 8.9%. The median age in Seville is 49.9 years: 45.8 years for males, and 54.4 years for females. For every 100 females there are 87.7 males.
Data after 2023 is projected based on recent change
The racial composition of Seville includes 98.49% White, and smaller percentages for Two or more races, other race and multiracial populations.
White (98.49%)
Two or more races (1.32%)
Other race (0.19%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 2,083 | 98.49% |
| Two or more races | 28 | 1.32% |
| Other race | 4 | 0.19% |
Married
Widowed
Divorced
Separated
Never Married
Seville's average per capita income is $47,679. Household income levels show a median of $73,698. The poverty rate stands at 8.9%.
Name | Median | Mean |
|---|---|---|
| Married Families | $81,725 | - |
| Families | $81,708 | $99,785 |
| Households | $73,698 | $83,681 |
| Non Families | $42,500 | $57,691 |
Average Income
Median Household Income
Poverty Rate