Sandy Lake township is located in Mercer County, Pennsylvania. Sandy Lake township has a 2026 population of 1,190. Sandy Lake township is currently growing at a rate of 0.17% annually but its population has decreased by -0.5% since the most recent census, which recorded a population of 1,196 in 2020.
The median household income in Sandy Lake township is $61,458 with a poverty rate of 9.17%. The median age in Sandy Lake township is 48.1 years: 52.4 years for males, and 43.2 years for females. For every 100 females there are 108.6 males.
Data after 2023 is projected based on recent change
Overall: 48.1 years
Female: 43.2 years
Male: 52.4 years
There are 949 adults, (316 of whom are seniors) in Sandy Lake township.
Female: 561 (47.9%)
Male: 609 (52.1%)
The racial composition of Sandy Lake township includes 90.09% White, 5.64% other race, and smaller percentages for Native American and multiracial populations.
| Race | Population ↓ | Percentage (of total) |
|---|---|---|
| White | 1,054 | 90.09% |
| Other race | 66 | 5.64% |
| Two or more races | 48 | 4.1% |
| Native American | 2 | 0.17% |
Sandy Lake township 's average per capita income is $49,342. Household income levels show a median of $61,458. The poverty rate stands at 9.17%.
| Name | Median ↓ | Mean |
|---|---|---|
| Married Families | $80,000 | - |
| Families | $77,083 | $104,882 |
| Households | $61,458 | $91,589 |
| Non Families | $47,500 | $67,502 |
Average Income
Median Household Income
Poverty Rate