Sandy Lake township is located in Mercer County, Pennsylvania. Sandy Lake township has a 2025 population of 1,174. Sandy Lake township is currently declining at a rate of -0.42% annually and its population has decreased by -1.84% since the most recent census, which recorded a population of 1,196 in 2020.
The average household income in Sandy Lake township is $89,204 with a poverty rate of 6.66%.The median age in Sandy Lake township is 49.9 years: 54 years for males, and 45.9 years for females.
Data after 2023 is projected based on recent change
The racial composition of Sandy Lake township includes 90.76% White, 5.46% other race, and smaller percentages for Native American and multiracial populations.
Race | Population | Percentage (of total) |
---|---|---|
White | 1,080 | 90.76% |
Other race | 65 | 5.46% |
Two or more races | 43 | 3.61% |
Native American | 2 | 0.17% |
Married
Widowed
Divorced
Separated
Never Married
Sandy Lake township's average per capita income is $47,500. Household income levels show a median of $61,012. The poverty rate stands at 6.66%.
Name | Median | Mean |
---|---|---|
Families | $75,500 | $100,596 |
Married Families | $75,375 | - |
Households | $61,012 | $89,204 |
Non Families | $53,015 | $66,608 |
Average Income
Median Household Income
Poverty Rate