Shrewsbury is located in Rutland County, Vermont. Shrewsbury has a 2025 population of 1,098 . Shrewsbury is currently declining at a rate of -0.09% annually but its population has increased by 0.27% since the most recent census, which recorded a population of 1,095 in 2020.
The average household income in Shrewsbury is $102,787 with a poverty rate of 5.52%. The median age in Shrewsbury is 41.1 years: 40.1 years for males, and 42.2 years for females. For every 100 females there are 107.3 males.
Data after 2023 is projected based on recent change
The racial composition of Shrewsbury includes 90.64% White, and smaller percentages for Black or African American, Asian, other race and multiracial populations.
White (90.64%)
Two or more races (6%)
Black or African American (2%)
Asian (0.8%)
Other race (0.56%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 1,133 | 90.64% |
| Two or more races | 75 | 6% |
| Black or African American | 25 | 2% |
| Asian | 10 | 0.8% |
| Other race | 7 | 0.56% |
Married
Widowed
Divorced
Separated
Never Married
Shrewsbury's average per capita income is $45,750. Household income levels show a median of $86,250. The poverty rate stands at 5.52%.
Name | Median | Mean |
|---|---|---|
| Married Families | $97,679 | - |
| Families | $92,917 | $105,886 |
| Households | $86,250 | $102,787 |
| Non Families | $51,563 | $93,361 |
Average Income
Median Household Income
Poverty Rate