Shrewsbury town is located in Rutland County, Vermont. Shrewsbury town has a 2026 population of 1,099. Shrewsbury town is currently declining at a rate of -0.09% annually but its population has increased by 0.37% since the most recent census, which recorded a population of 1,095 in 2020.
The median household income in Shrewsbury town is $86,250 with a poverty rate of 5.52%. The median age in Shrewsbury town is 41.1 years: 40.1 years for males, and 42.2 years for females. For every 100 females there are 107.3 males.
Data after 2023 is projected based on recent change
The racial composition of Shrewsbury town includes 90.64% White, and smaller percentages for Black or African American, Asian, other race and multiracial populations.
White (90.64%)
Two or more races (6%)
Black or African American (2%)
Asian (0.8%)
Other race (0.56%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 1,133 | 90.64% |
| Two or more races | 75 | 6% |
| Black or African American | 25 | 2% |
| Asian | 10 | 0.8% |
| Other race | 7 | 0.56% |
Married
Widowed
Divorced
Separated
Never Married
Shrewsbury town's average per capita income is $45,750. Household income levels show a median of $86,250. The poverty rate stands at 5.52%.
Name | Median | Mean |
|---|---|---|
| Married Families | $97,679 | - |
| Families | $92,917 | $105,886 |
| Households | $86,250 | $102,787 |
| Non Families | $51,563 | $93,361 |
Average Income
Median Household Income
Poverty Rate