Janesville is a city located in Bremer County, Iowa. Janesville has a 2026 population of 1,059. Janesville is currently growing at a rate of 0.38% annually and its population has increased by 2.12% since the most recent census, which recorded a population of 1,037 in 2020.
The median household income in Janesville is $103,542 with a poverty rate of 5.45%. The median age in Janesville is 47 years: 44.8 years for males, and 50 years for females. For every 100 females there are 105.6 males.
Data after 2023 is projected based on recent change
Overall: 47 years
Female: 50 years
Male: 44.8 years
There are 723 adults, (142 of whom are seniors) in Janesville.
Female: 446 (48.6%)
Male: 471 (51.4%)
The racial composition of Janesville includes 97.38% White, and smaller percentages for Asian, other race, Two or more races and multiracial populations.
| Race | Population ↓ | Percentage (of total) |
|---|---|---|
| White | 893 | 97.38% |
| Asian | 10 | 1.09% |
| Other race | 9 | 0.98% |
| Two or more races | 5 | 0.55% |
Janesville 's average per capita income is $58,690. Household income levels show a median of $103,542. The poverty rate stands at 5.45%.
| Name | Median ↓ | Mean |
|---|---|---|
| Families | $118,000 | $119,383 |
| Married Families | $114,417 | - |
| Households | $103,542 | $103,900 |
| Non Families | $42,708 | $50,379 |
Average Income
Median Household Income
Poverty Rate