Liberty township is located in Woodbury County, Iowa Iowa. Unfortunately, the data for this location is currently limited or unavailable.
The median household income in Liberty township is $75,000 with a poverty rate of 3.6%. The median age in Liberty township is 37.4 years: 38.8 years for males, and 36.8 years for females. For every 100 females there are 102.4 males.
No data available.
The racial composition of Liberty township includes 91.2% White, and smaller percentages for Native American and multiracial populations.
White (91.2%)
Two or more races (8.6%)
Native American (0.2%)
Race | Population | Percentage (of total) |
|---|---|---|
| White | 912 | 91.2% |
| Two or more races | 86 | 8.6% |
| Native American | 2 | 0.2% |
Married
Widowed
Divorced
Separated
Never Married
Liberty township's average per capita income is $52,763. Household income levels show a median of $75,000. The poverty rate stands at 3.6%.
Name | Median | Mean |
|---|---|---|
| Married Families | $102,000 | - |
| Families | $83,500 | $102,196 |
| Households | $75,000 | $84,318 |
| Non Families | $32,321 | $40,802 |
Average Income
Median Household Income
Poverty Rate