Seville is a city located in Medina County Ohio. Seville has a 2020 population of 2,464. Seville is currently growing at a rate of 0.53% annually and its population has increased by 6.67% since the most recent census, which recorded a population of 2,310 in 2010.
The average household income in Seville is $72,027 with a poverty rate of 9.38%. The median rental costs in recent years comes to $839 per month, and the median house value is $140,900. The median age in Seville is 40.2 years, 37.7 years for males, and 40.7 years for females.
According to the most recent ACS, the racial composition of Sevillewas:
The highest rate of high school graduation is among black people with a rate of 100.00%.
The highest rate of bachelors degrees is among hispanic people with a rate of 42.11%.
98.53% of Seville residents speak only English, while 1.47% speak other languages. The non-English language spoken by the largest group is Spanish, which is spoken by 0.94% of the population.
Overall Poverty Rate
Male Poverty Rate
Female Poverty Rate
The race most likely to be in poverty in Seville is Black, with 100.00% below the poverty level.
The race least likely to be in poverty in Seville is Other, with NaN% below the poverty level.
The poverty rate among those that worked full-time for the past 12 months was 0.73%. Among those working part-time, it was 12.17%, and for those that did not work, the poverty rate was 11.93%.
Veteran Poverty Rate
Veteran Disability Rate
Labor Force Participation
Non citizens include legal permanent residents (green card holders), international students, temporary workers, humanitarian migrants, and illegal immigrants.
Born in Seville
99.36% of Seville residents were born in the United States, with 79.35% having been born in Ohio. 0.45% of residents are not US citizens. Of those not born in the United States, the largest percentage are from Latin America.